(x^2-x)^2-8(x^2-x)+12=0

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Solution for (x^2-x)^2-8(x^2-x)+12=0 equation:



(x^2-x)^2-8(x^2-x)+12=0
We multiply parentheses
-8x^2+(x^2-x)^2+8x+12=0
We add all the numbers together, and all the variables
-8x^2+8x+(x^2-x)^2+12=0
We move all terms containing x to the left, all other terms to the right
-8x^2+8x+(x^2-x)^2=-12

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